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13311302299993 is a prime number
BaseRepresentation
bin1100000110110100011101…
…1100011111000101011001
31202010112210112200212220001
43001231013130133011121
53221043021342044433
644151043341133001
72542465323446005
oct301550734370531
952115715625801
1013311302299993
11427232313a295
1215ab9a025a161
137573342362a9
143403b0249705
151813ce1ea57d
hexc1b4771f159

13311302299993 has 2 divisors, whose sum is σ = 13311302299994. Its totient is φ = 13311302299992.

The previous prime is 13311302299969. The next prime is 13311302300011. The reversal of 13311302299993 is 39999220311331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11865565397449 + 1445736902544 = 3444643^2 + 1202388^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311302299993 - 217 = 13311302168921 is a prime.

It is not a weakly prime, because it can be changed into another prime (13311302299903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655651149996 + 6655651149997.

It is an arithmetic number, because the mean of its divisors is an integer number (6655651149997).

Almost surely, 213311302299993 is an apocalyptic number.

It is an amenable number.

13311302299993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311302299993 is an equidigital number, since it uses as much as digits as its factorization.

13311302299993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2125764, while the sum is 55.

The spelling of 13311302299993 in words is "thirteen trillion, three hundred eleven billion, three hundred two million, two hundred ninety-nine thousand, nine hundred ninety-three".