Base | Representation |
---|---|
bin | 1100000110110100011101… |
… | …1111010010000000110111 |
3 | 1202010112210121002010020021 |
4 | 3001231013133102000313 |
5 | 3221043022034023022 |
6 | 44151043404550011 |
7 | 2542465332620506 |
oct | 301550737220067 |
9 | 52115717063207 |
10 | 13311303032887 |
11 | 427232359a992 |
12 | 15ab9a0552307 |
13 | 757334431a62 |
14 | 3403b039a83d |
15 | 1813ce2e27c7 |
hex | c1b477d2037 |
13311303032887 has 2 divisors, whose sum is σ = 13311303032888. Its totient is φ = 13311303032886.
The previous prime is 13311303032879. The next prime is 13311303033011. The reversal of 13311303032887 is 78823030311331.
13311303032887 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13311303032887 - 23 = 13311303032879 is a prime.
It is a super-3 number, since 3×133113030328873 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13311303032387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655651516443 + 6655651516444.
It is an arithmetic number, because the mean of its divisors is an integer number (6655651516444).
Almost surely, 213311303032887 is an apocalyptic number.
13311303032887 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311303032887 is an equidigital number, since it uses as much as digits as its factorization.
13311303032887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 43.
The spelling of 13311303032887 in words is "thirteen trillion, three hundred eleven billion, three hundred three million, thirty-two thousand, eight hundred eighty-seven".
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