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13311303032887 is a prime number
BaseRepresentation
bin1100000110110100011101…
…1111010010000000110111
31202010112210121002010020021
43001231013133102000313
53221043022034023022
644151043404550011
72542465332620506
oct301550737220067
952115717063207
1013311303032887
11427232359a992
1215ab9a0552307
13757334431a62
143403b039a83d
151813ce2e27c7
hexc1b477d2037

13311303032887 has 2 divisors, whose sum is σ = 13311303032888. Its totient is φ = 13311303032886.

The previous prime is 13311303032879. The next prime is 13311303033011. The reversal of 13311303032887 is 78823030311331.

13311303032887 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13311303032887 - 23 = 13311303032879 is a prime.

It is a super-3 number, since 3×133113030328873 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311303032387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655651516443 + 6655651516444.

It is an arithmetic number, because the mean of its divisors is an integer number (6655651516444).

Almost surely, 213311303032887 is an apocalyptic number.

13311303032887 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311303032887 is an equidigital number, since it uses as much as digits as its factorization.

13311303032887 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 13311303032887 in words is "thirteen trillion, three hundred eleven billion, three hundred three million, thirty-two thousand, eight hundred eighty-seven".