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13311311030161 is a prime number
BaseRepresentation
bin1100000110110100011111…
…1101110010011110010001
31202010112211011010102102121
43001231013331302132101
53221043031110431121
644151044252214241
72542465460606254
oct301550775623621
952115734112377
1013311311030161
114272328062401
1215ab9a316a381
13757335ca1b81
143403b147d09b
151813ced72141
hexc1b47f72791

13311311030161 has 2 divisors, whose sum is σ = 13311311030162. Its totient is φ = 13311311030160.

The previous prime is 13311311030137. The next prime is 13311311030231. The reversal of 13311311030161 is 16103011311331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13177771214400 + 133539815761 = 3630120^2 + 365431^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311311030161 - 233 = 13302721095569 is a prime.

It is a super-3 number, since 3×133113110301613 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13311311030111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655655515080 + 6655655515081.

It is an arithmetic number, because the mean of its divisors is an integer number (6655655515081).

Almost surely, 213311311030161 is an apocalyptic number.

It is an amenable number.

13311311030161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311311030161 is an equidigital number, since it uses as much as digits as its factorization.

13311311030161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 25.

Adding to 13311311030161 its reverse (16103011311331), we get a palindrome (29414322341492).

The spelling of 13311311030161 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, thirty thousand, one hundred sixty-one".