Base | Representation |
---|---|
bin | 11110010001000011010001… |
… | …000001101000011000101111 |
3 | 122110022111021010112211201222 |
4 | 132101003101001220120233 |
5 | 114421411144111201333 |
6 | 1151035155040453555 |
7 | 40016051351161304 |
oct | 3621032101503057 |
9 | 573274233484658 |
10 | 133113133303343 |
11 | 39460a65552206 |
12 | 12b1a27301a2bb |
13 | 593768c79a71b |
14 | 24c29d24610ab |
15 | 105c8a100b298 |
hex | 7910d106862f |
133113133303343 has 2 divisors, whose sum is σ = 133113133303344. Its totient is φ = 133113133303342.
The previous prime is 133113133303273. The next prime is 133113133303363. The reversal of 133113133303343 is 343303331311331.
It is a strong prime.
It is an emirp because it is prime and its reverse (343303331311331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133113133303343 - 234 = 133095953434159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133113133303363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556566651671 + 66556566651672.
It is an arithmetic number, because the mean of its divisors is an integer number (66556566651672).
Almost surely, 2133113133303343 is an apocalyptic number.
133113133303343 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113133303343 is an equidigital number, since it uses as much as digits as its factorization.
133113133303343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 35.
Adding to 133113133303343 its reverse (343303331311331), we get a palindrome (476416464614674).
The spelling of 133113133303343 in words is "one hundred thirty-three trillion, one hundred thirteen billion, one hundred thirty-three million, three hundred three thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •