1331131423 has 2 divisors, whose sum is σ = 1331131424. Its totient is φ = 1331131422.

The previous prime is 1331131409. The next prime is 1331131427. The reversal of 1331131423 is 3241311331.

It is a strong prime.

It is an emirp because it is prime and its reverse (3241311331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331131423 - 2¹⁷ = 1331000351 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331131394 and 1331131403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331131427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665565711 + 665565712.

It is an arithmetic number, because the mean of its divisors is an integer number (665565712).

Almost surely, 2^1331131423 is an apocalyptic number.

1331131423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331131423 is an equidigital number, since it uses as much as digits as its factorization.

1331131423 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 22.

The square root of 1331131423 is about 36484.6738096971. The cubic root of 1331131423 is about 1100.0362034916.

Adding to 1331131423 its reverse (3241311331), we get a palindrome (4572442754).

The spelling of 1331131423 in words is "one billion, three hundred thirty-one million, one hundred thirty-one thousand, four hundred twenty-three".