Base | Representation |
---|---|
bin | 11110010001000011010101… |
… | …000000111100011001001100 |
3 | 122110022111102210111011121120 |
4 | 132101003111000330121030 |
5 | 114421411313224411022 |
6 | 1151035205431200540 |
7 | 40016053123103520 |
oct | 3621032500743114 |
9 | 573274383434546 |
10 | 133113200232012 |
11 | 39460a9a305760 |
12 | 12b1a291516150 |
13 | 59376a06022a0 |
14 | 24c29db2c3d80 |
15 | 105c8a6d2bd5c |
hex | 7910d503c64c |
133113200232012 has 768 divisors, whose sum is σ = 456469055078400. Its totient is φ = 29041361879040.
The previous prime is 133113200231981. The next prime is 133113200232043. The reversal of 133113200232012 is 210232002311331.
It is an interprime number because it is at equal distance from previous prime (133113200231981) and next prime (133113200232043).
It is a super-4 number, since 4×1331132002320124 (a number of 58 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 1277340013 + ... + 1277444219.
It is an arithmetic number, because the mean of its divisors is an integer number (594360748800).
Almost surely, 2133113200232012 is an apocalyptic number.
133113200232012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133113200232012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (228234527539200).
133113200232012 is an abundant number, since it is smaller than the sum of its proper divisors (323355854846388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133113200232012 is a wasteful number, since it uses less digits than its factorization.
133113200232012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104486 (or 104484 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 133113200232012 its reverse (210232002311331), we get a palindrome (343345202543343).
The spelling of 133113200232012 in words is "one hundred thirty-three trillion, one hundred thirteen billion, two hundred million, two hundred thirty-two thousand, twelve".
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