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133113200310001 is a prime number
BaseRepresentation
bin11110010001000011010101…
…000001001111011011110001
3122110022111102210122010121001
4132101003111001033123301
5114421411313234410001
61151035205433002001
740016053123550062
oct3621032501173361
9573274383563531
10133113200310001
1139460a9a35930a
1212b1a291553301
1359376a062b932
1424c29db304569
15105c8a6d45001
hex7910d504f6f1

133113200310001 has 2 divisors, whose sum is σ = 133113200310002. Its totient is φ = 133113200310000.

The previous prime is 133113200309983. The next prime is 133113200310047. The reversal of 133113200310001 is 100013002311331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86576995464976 + 46536204845025 = 9304676^2 + 6821745^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133113200310001 is a prime.

It is not a weakly prime, because it can be changed into another prime (133113200310091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556600155000 + 66556600155001.

It is an arithmetic number, because the mean of its divisors is an integer number (66556600155001).

Almost surely, 2133113200310001 is an apocalyptic number.

It is an amenable number.

133113200310001 is a deficient number, since it is larger than the sum of its proper divisors (1).

133113200310001 is an equidigital number, since it uses as much as digits as its factorization.

133113200310001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 133113200310001 its reverse (100013002311331), we get a palindrome (233126202621332).

The spelling of 133113200310001 in words is "one hundred thirty-three trillion, one hundred thirteen billion, two hundred million, three hundred ten thousand, one".