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133114112444447 is a prime number
BaseRepresentation
bin11110010001000100001011…
…011000110000100000011111
3122110022120210100222100211022
4132101010023120300200133
5114421420200241210242
61151035440135114355
740016114540555141
oct3621041330604037
9573276710870738
10133114112444447
1139461418219432
1212b1a4a6b129bb
1359377b75b3564
1424c2a864dcc91
15105c90be6c0d2
hex79110b63081f

133114112444447 has 2 divisors, whose sum is σ = 133114112444448. Its totient is φ = 133114112444446.

The previous prime is 133114112444363. The next prime is 133114112444503. The reversal of 133114112444447 is 744444211411331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133114112444447 - 28 = 133114112444191 is a prime.

It is a super-2 number, since 2×1331141124444472 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133114112444398 and 133114112444407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133114112744447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66557056222223 + 66557056222224.

It is an arithmetic number, because the mean of its divisors is an integer number (66557056222224).

Almost surely, 2133114112444447 is an apocalyptic number.

133114112444447 is a deficient number, since it is larger than the sum of its proper divisors (1).

133114112444447 is an equidigital number, since it uses as much as digits as its factorization.

133114112444447 is an evil number, because the sum of its binary digits is even.

The product of its digits is 516096, while the sum is 44.

Adding to 133114112444447 its reverse (744444211411331), we get a palindrome (877558323855778).

The spelling of 133114112444447 in words is "one hundred thirty-three trillion, one hundred fourteen billion, one hundred twelve million, four hundred forty-four thousand, four hundred forty-seven".