Base | Representation |
---|---|
bin | 1100000110110100111010… |
… | …1101001000011111010011 |
3 | 1202010120010000220012010111 |
4 | 3001231032231020133103 |
5 | 3221043244032320103 |
6 | 44151103411542151 |
7 | 2542501332663625 |
oct | 301551655103723 |
9 | 52116100805114 |
10 | 13311424104403 |
11 | 4272385973797 |
12 | 15aba14bba957 |
13 | 7573535425c9 |
14 | 3403c24b4c15 |
15 | 1813d9c5a86d |
hex | c1b4eb487d3 |
13311424104403 has 8 divisors (see below), whose sum is σ = 13325967019728. Its totient is φ = 13296882217344.
The previous prime is 13311424104343. The next prime is 13311424104487. The reversal of 13311424104403 is 30440142411331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13311424104403 - 225 = 13311390549971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13311424104493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27252175 + ... + 27736327.
It is an arithmetic number, because the mean of its divisors is an integer number (1665745877466).
Almost surely, 213311424104403 is an apocalyptic number.
13311424104403 is a deficient number, since it is larger than the sum of its proper divisors (14542915325).
13311424104403 is an equidigital number, since it uses as much as digits as its factorization.
13311424104403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 514133.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13311424104403 its reverse (30440142411331), we get a palindrome (43751566515734).
The spelling of 13311424104403 in words is "thirteen trillion, three hundred eleven billion, four hundred twenty-four million, one hundred four thousand, four hundred three".
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