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13311424420303 = 34217389029559
BaseRepresentation
bin1100000110110100111010…
…1110010101100111001111
31202010120010001111020110111
43001231032232111213033
53221043244122422203
644151103422420451
72542501335450622
oct301551656254717
952116101436414
1013311424420303
11427238606a069
1215aba15131727
13757353623329
143403c2557db9
151813d9cbe26d
hexc1b4eb959cf

13311424420303 has 4 divisors (see below), whose sum is σ = 13311813484080. Its totient is φ = 13311035356528.

The previous prime is 13311424420253. The next prime is 13311424420337. The reversal of 13311424420303 is 30302442411331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13311424420303 - 233 = 13302834485711 is a prime.

It is a super-2 number, since 2×133114244203032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311424420373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194480563 + ... + 194548996.

It is an arithmetic number, because the mean of its divisors is an integer number (3327953371020).

Almost surely, 213311424420303 is an apocalyptic number.

13311424420303 is a deficient number, since it is larger than the sum of its proper divisors (389063777).

13311424420303 is an equidigital number, since it uses as much as digits as its factorization.

13311424420303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 389063776.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13311424420303 its reverse (30302442411331), we get a palindrome (43613866831634).

The spelling of 13311424420303 in words is "thirteen trillion, three hundred eleven billion, four hundred twenty-four million, four hundred twenty thousand, three hundred three".

Divisors: 1 34217 389029559 13311424420303