Base | Representation |
---|---|
bin | 1100000110110100111110… |
… | …1001110110001101001111 |
3 | 1202010120011010211210122021 |
4 | 3001231033221312031033 |
5 | 3221043312121122203 |
6 | 44151105141031011 |
7 | 2542501615162645 |
oct | 301551751661517 |
9 | 52116133753567 |
10 | 13311440020303 |
11 | 4272393954627 |
12 | 15aba1a3b5467 |
13 | 757356925ab9 |
14 | 3403c4659195 |
15 | 1813db3515bd |
hex | c1b4fa7634f |
13311440020303 has 2 divisors, whose sum is σ = 13311440020304. Its totient is φ = 13311440020302.
The previous prime is 13311440020283. The next prime is 13311440020309. The reversal of 13311440020303 is 30302004411331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311440020303 - 221 = 13311437923151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13311440020309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655720010151 + 6655720010152.
It is an arithmetic number, because the mean of its divisors is an integer number (6655720010152).
Almost surely, 213311440020303 is an apocalyptic number.
13311440020303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311440020303 is an equidigital number, since it uses as much as digits as its factorization.
13311440020303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13311440020303 its reverse (30302004411331), we get a palindrome (43613444431634).
The spelling of 13311440020303 in words is "thirteen trillion, three hundred eleven billion, four hundred forty million, twenty thousand, three hundred three".
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