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133115312113243 is a prime number
BaseRepresentation
bin11110010001000101010010…
…111001001000011001011011
3122110022200212222100212000221
4132101011102321020121123
5114421430124400110433
61151040155152140511
740016156345563615
oct3621052271103133
9573280788325027
10133115312113243
1139461983419349
1212b1a780837737
135937948cc0055
1424c2b5b983db5
15105c97c43e72d
hex791152e4865b

133115312113243 has 2 divisors, whose sum is σ = 133115312113244. Its totient is φ = 133115312113242.

The previous prime is 133115312113237. The next prime is 133115312113253. The reversal of 133115312113243 is 342311213511331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133115312113243 - 229 = 133114775242331 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133115312113199 and 133115312113208.

It is not a weakly prime, because it can be changed into another prime (133115312113253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66557656056621 + 66557656056622.

It is an arithmetic number, because the mean of its divisors is an integer number (66557656056622).

Almost surely, 2133115312113243 is an apocalyptic number.

133115312113243 is a deficient number, since it is larger than the sum of its proper divisors (1).

133115312113243 is an equidigital number, since it uses as much as digits as its factorization.

133115312113243 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19440, while the sum is 34.

Adding to 133115312113243 its reverse (342311213511331), we get a palindrome (475426525624574).

The spelling of 133115312113243 in words is "one hundred thirty-three trillion, one hundred fifteen billion, three hundred twelve million, one hundred thirteen thousand, two hundred forty-three".