Base | Representation |
---|---|
bin | 11110010001000101010010… |
… | …111001001000011001011011 |
3 | 122110022200212222100212000221 |
4 | 132101011102321020121123 |
5 | 114421430124400110433 |
6 | 1151040155152140511 |
7 | 40016156345563615 |
oct | 3621052271103133 |
9 | 573280788325027 |
10 | 133115312113243 |
11 | 39461983419349 |
12 | 12b1a780837737 |
13 | 5937948cc0055 |
14 | 24c2b5b983db5 |
15 | 105c97c43e72d |
hex | 791152e4865b |
133115312113243 has 2 divisors, whose sum is σ = 133115312113244. Its totient is φ = 133115312113242.
The previous prime is 133115312113237. The next prime is 133115312113253. The reversal of 133115312113243 is 342311213511331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133115312113243 - 229 = 133114775242331 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133115312113199 and 133115312113208.
It is not a weakly prime, because it can be changed into another prime (133115312113253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66557656056621 + 66557656056622.
It is an arithmetic number, because the mean of its divisors is an integer number (66557656056622).
Almost surely, 2133115312113243 is an apocalyptic number.
133115312113243 is a deficient number, since it is larger than the sum of its proper divisors (1).
133115312113243 is an equidigital number, since it uses as much as digits as its factorization.
133115312113243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 34.
Adding to 133115312113243 its reverse (342311213511331), we get a palindrome (475426525624574).
The spelling of 133115312113243 in words is "one hundred thirty-three trillion, one hundred fifteen billion, three hundred twelve million, one hundred thirteen thousand, two hundred forty-three".
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