Base | Representation |
---|---|
bin | 111101111111001100… |
… | …1010100110101111111 |
3 | 110201121011020211210111 |
4 | 1323332121110311333 |
5 | 4140110432230334 |
6 | 141053024450451 |
7 | 12421523301043 |
oct | 1737631246577 |
9 | 421534224714 |
10 | 133117070719 |
11 | 51500130536 |
12 | 21970779a27 |
13 | c7258c8889 |
14 | 662b468023 |
15 | 36e1830064 |
hex | 1efe654d7f |
133117070719 has 2 divisors, whose sum is σ = 133117070720. Its totient is φ = 133117070718.
The previous prime is 133117070689. The next prime is 133117070771. The reversal of 133117070719 is 917070711331.
It is a weak prime.
It is an emirp because it is prime and its reverse (917070711331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133117070719 - 217 = 133116939647 is a prime.
It is a super-2 number, since 2×1331170707192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133117077719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66558535359 + 66558535360.
It is an arithmetic number, because the mean of its divisors is an integer number (66558535360).
Almost surely, 2133117070719 is an apocalyptic number.
133117070719 is a deficient number, since it is larger than the sum of its proper divisors (1).
133117070719 is an equidigital number, since it uses as much as digits as its factorization.
133117070719 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27783, while the sum is 40.
The spelling of 133117070719 in words is "one hundred thirty-three billion, one hundred seventeen million, seventy thousand, seven hundred nineteen".
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