Base | Representation |
---|---|
bin | 10011010111110000101… |
… | …101001000000011111111 |
3 | 11201021000110010222102102 |
4 | 103113300231020003333 |
5 | 133302230403141212 |
6 | 2455312005015315 |
7 | 165113650656536 |
oct | 23276055100377 |
9 | 4637013128372 |
10 | 1331183255807 |
11 | 473608275889 |
12 | 195baa6b453b |
13 | 986b76704b2 |
14 | 48602c0531d |
15 | 2496187d5c2 |
hex | 135f0b480ff |
1331183255807 has 2 divisors, whose sum is σ = 1331183255808. Its totient is φ = 1331183255806.
The previous prime is 1331183255741. The next prime is 1331183255827. The reversal of 1331183255807 is 7085523811331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331183255807 - 28 = 1331183255551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331183255827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665591627903 + 665591627904.
It is an arithmetic number, because the mean of its divisors is an integer number (665591627904).
Almost surely, 21331183255807 is an apocalyptic number.
1331183255807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331183255807 is an equidigital number, since it uses as much as digits as its factorization.
1331183255807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 47.
The spelling of 1331183255807 in words is "one trillion, three hundred thirty-one billion, one hundred eighty-three million, two hundred fifty-five thousand, eight hundred seven".
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