Base | Representation |
---|---|
bin | 11110010001001001101000… |
… | …100011101100111000111101 |
3 | 122110100010220122001112211011 |
4 | 132101021220203230320331 |
5 | 114422014144430432342 |
6 | 1151042245322555221 |
7 | 40016412653001655 |
oct | 3621115043547075 |
9 | 573303818045734 |
10 | 133119970561597 |
11 | 39463953a51568 |
12 | 12b1b660968b11 |
13 | 593820c162c76 |
14 | 24c3080537365 |
15 | 105cb513ca717 |
hex | 7912688ece3d |
133119970561597 has 2 divisors, whose sum is σ = 133119970561598. Its totient is φ = 133119970561596.
The previous prime is 133119970561553. The next prime is 133119970561619. The reversal of 133119970561597 is 795165079911331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128064281269401 + 5055689292196 = 11316549^2 + 2248486^2 .
It is a cyclic number.
It is not a de Polignac number, because 133119970561597 - 215 = 133119970528829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133119970511597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66559985280798 + 66559985280799.
It is an arithmetic number, because the mean of its divisors is an integer number (66559985280799).
Almost surely, 2133119970561597 is an apocalyptic number.
It is an amenable number.
133119970561597 is a deficient number, since it is larger than the sum of its proper divisors (1).
133119970561597 is an equidigital number, since it uses as much as digits as its factorization.
133119970561597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48223350, while the sum is 67.
The spelling of 133119970561597 in words is "one hundred thirty-three trillion, one hundred nineteen billion, nine hundred seventy million, five hundred sixty-one thousand, five hundred ninety-seven".
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