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133119970561597 is a prime number
BaseRepresentation
bin11110010001001001101000…
…100011101100111000111101
3122110100010220122001112211011
4132101021220203230320331
5114422014144430432342
61151042245322555221
740016412653001655
oct3621115043547075
9573303818045734
10133119970561597
1139463953a51568
1212b1b660968b11
13593820c162c76
1424c3080537365
15105cb513ca717
hex7912688ece3d

133119970561597 has 2 divisors, whose sum is σ = 133119970561598. Its totient is φ = 133119970561596.

The previous prime is 133119970561553. The next prime is 133119970561619. The reversal of 133119970561597 is 795165079911331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128064281269401 + 5055689292196 = 11316549^2 + 2248486^2 .

It is a cyclic number.

It is not a de Polignac number, because 133119970561597 - 215 = 133119970528829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133119970511597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66559985280798 + 66559985280799.

It is an arithmetic number, because the mean of its divisors is an integer number (66559985280799).

Almost surely, 2133119970561597 is an apocalyptic number.

It is an amenable number.

133119970561597 is a deficient number, since it is larger than the sum of its proper divisors (1).

133119970561597 is an equidigital number, since it uses as much as digits as its factorization.

133119970561597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48223350, while the sum is 67.

The spelling of 133119970561597 in words is "one hundred thirty-three trillion, one hundred nineteen billion, nine hundred seventy million, five hundred sixty-one thousand, five hundred ninety-seven".