Base | Representation |
---|---|
bin | 10011010111110001101… |
… | …101011111101111111111 |
3 | 11201021001121220021112021 |
4 | 103113301231133233333 |
5 | 133302244213130142 |
6 | 2455313410421011 |
7 | 165114244256554 |
oct | 23276155375777 |
9 | 4637047807467 |
10 | 1331200130047 |
11 | 473616850737 |
12 | 195bb4291767 |
13 | 986baccac58 |
14 | 48605158a2b |
15 | 249630b3267 |
hex | 135f1b5fbff |
1331200130047 has 2 divisors, whose sum is σ = 1331200130048. Its totient is φ = 1331200130046.
The previous prime is 1331200130027. The next prime is 1331200130059. The reversal of 1331200130047 is 7400310021331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331200130047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331200130027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665600065023 + 665600065024.
It is an arithmetic number, because the mean of its divisors is an integer number (665600065024).
Almost surely, 21331200130047 is an apocalyptic number.
1331200130047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331200130047 is an equidigital number, since it uses as much as digits as its factorization.
1331200130047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1331200130047 its reverse (7400310021331), we get a palindrome (8731510151378).
The spelling of 1331200130047 in words is "one trillion, three hundred thirty-one billion, two hundred million, one hundred thirty thousand, forty-seven".
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