Base | Representation |
---|---|
bin | 1100000110110111000100… |
… | …1010110001110001001011 |
3 | 1202010121121022212121202101 |
4 | 3001231301022301301023 |
5 | 3221100440042113003 |
6 | 44151241024414231 |
7 | 2542521553403200 |
oct | 301556112616113 |
9 | 52117538777671 |
10 | 13312002301003 |
11 | 427265228a41a |
12 | 15abb56777377 |
13 | 757416275c83 |
14 | 3404391c3ca7 |
15 | 1814208bd11d |
hex | c1b712b1c4b |
13312002301003 has 12 divisors (see below), whose sum is σ = 15485558932272. Its totient is φ = 11410163528400.
The previous prime is 13312002300941. The next prime is 13312002301027. The reversal of 13312002301003 is 30010320021331.
It is not a de Polignac number, because 13312002301003 - 213 = 13312002292811 is a prime.
It is a super-2 number, since 2×133120023010032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13312002301093) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3222001 + ... + 6083197.
It is an arithmetic number, because the mean of its divisors is an integer number (1290463244356).
Almost surely, 213312002301003 is an apocalyptic number.
13312002301003 is a deficient number, since it is larger than the sum of its proper divisors (2173556631269).
13312002301003 is an equidigital number, since it uses as much as digits as its factorization.
13312002301003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2956162 (or 2956155 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13312002301003 its reverse (30010320021331), we get a palindrome (43322322322334).
The spelling of 13312002301003 in words is "thirteen trillion, three hundred twelve billion, two million, three hundred one thousand, three".
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