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133120113330 = 2354437337111
BaseRepresentation
bin111101111111010010…
…0111011101010110010
3110201121100222102110210
41323332210323222302
54140112222111310
6141053214004550
712421561202451
oct1737644735262
9421540872423
10133120113330
1151501919496
12219717a6756
13c726422739
14662ba1ab98
1536e1c31820
hex1efe93bab2

133120113330 has 16 divisors (see below), whose sum is σ = 319488272064. Its totient is φ = 35498696880.

The previous prime is 133120113281. The next prime is 133120113331. The reversal of 133120113330 is 33311021331.

It is a junction number, because it is equal to n+sod(n) for n = 133120113297 and 133120113306.

It is not an unprimeable number, because it can be changed into a prime (133120113331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2218668526 + ... + 2218668585.

It is an arithmetic number, because the mean of its divisors is an integer number (19968017004).

Almost surely, 2133120113330 is an apocalyptic number.

133120113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133120113330 is an abundant number, since it is smaller than the sum of its proper divisors (186368158734).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133120113330 is a wasteful number, since it uses less digits than its factorization.

133120113330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4437337121.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 133120113330 its reverse (33311021331), we get a palindrome (166431134661).

The spelling of 133120113330 in words is "one hundred thirty-three billion, one hundred twenty million, one hundred thirteen thousand, three hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 4437337111 8874674222 13312011333 22186685555 26624022666 44373371110 66560056665 133120113330