Base | Representation |
---|---|
bin | 10011010111110001110… |
… | …100101101011111010010 |
3 | 11201021001202110100212210 |
4 | 103113301310231133102 |
5 | 133302300204140310 |
6 | 2455313515132550 |
7 | 165114266324526 |
oct | 23276164553722 |
9 | 4637052410783 |
10 | 1331202021330 |
11 | 473617922685 |
12 | 195bb4a44156 |
13 | 986bb510a5c |
14 | 486054cbd86 |
15 | 24963338820 |
hex | 135f1d2d7d2 |
1331202021330 has 32 divisors (see below), whose sum is σ = 3194960977728. Its totient is φ = 354978747200.
The previous prime is 1331202021299. The next prime is 1331202021341. The reversal of 1331202021330 is 331202021331.
It is a junction number, because it is equal to n+sod(n) for n = 1331202021297 and 1331202021306.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 806665 + ... + 1820195.
It is an arithmetic number, because the mean of its divisors is an integer number (99842530554).
Almost surely, 21331202021330 is an apocalyptic number.
1331202021330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1331202021330 is an abundant number, since it is smaller than the sum of its proper divisors (1863758956398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1331202021330 is a wasteful number, since it uses less digits than its factorization.
1331202021330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1057322.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1331202021330 its reverse (331202021331), we get a palindrome (1662404042661).
Subtracting from 1331202021330 its reverse (331202021331), we obtain a palindrome (999999999999).
The spelling of 1331202021330 in words is "one trillion, three hundred thirty-one billion, two hundred two million, twenty-one thousand, three hundred thirty".
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