1331203300081 has 2 divisors, whose sum is σ = 1331203300082. Its totient is φ = 1331203300080.

The previous prime is 1331203300079. The next prime is 1331203300111. The reversal of 1331203300081 is 1800033021331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1302316898481 + 28886401600 = 1141191^2 + 169960^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331203300081 - 2¹ = 1331203300079 is a prime.

It is a super-2 number, since 2×1331203300081² (a number of 25 digits) contains 22 as substring.

Together with 1331203300079, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1331203300981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665601650040 + 665601650041.

It is an arithmetic number, because the mean of its divisors is an integer number (665601650041).

Almost surely, 2^{1331203300081} is an apocalyptic number.

It is an amenable number.

1331203300081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331203300081 is an equidigital number, since it uses as much as digits as its factorization.

1331203300081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 1331203300081 in words is "one trillion, three hundred thirty-one billion, two hundred three million, three hundred thousand, eighty-one".