13312100333113 has 4 divisors (see below), whose sum is σ = 13317905874148. Its totient is φ = 13306294792080.

The previous prime is 13312100333107. The next prime is 13312100333123. The reversal of 13312100333113 is 31133300121331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1400511298624 + 11911589034489 = 1183432^2 + 3451317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13312100333113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13312100333123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2902767078 + ... + 2902771663.

It is an arithmetic number, because the mean of its divisors is an integer number (3329476468537).

Almost surely, 2^{13312100333113} is an apocalyptic number.

It is an amenable number.

13312100333113 is a deficient number, since it is larger than the sum of its proper divisors (5805541035).

13312100333113 is an equidigital number, since it uses as much as digits as its factorization.

13312100333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5805541034.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13312100333113 its reverse (31133300121331), we get a palindrome (44445400454444).

The spelling of 13312100333113 in words is "thirteen trillion, three hundred twelve billion, one hundred million, three hundred thirty-three thousand, one hundred thirteen".