Base | Representation |
---|---|
bin | 10011010111110010010… |
… | …111101111001000110010 |
3 | 11201021002101201211221011 |
4 | 103113302113233020302 |
5 | 133302310031444442 |
6 | 2455314444021134 |
7 | 165114440345563 |
oct | 23276227571062 |
9 | 4637071654834 |
10 | 1331211203122 |
11 | 473622024039 |
12 | 195bb7b317aa |
13 | 986c03a7078 |
14 | 486067dc16a |
15 | 2496404e117 |
hex | 135f25ef232 |
1331211203122 has 4 divisors (see below), whose sum is σ = 1996816804686. Its totient is φ = 665605601560.
The previous prime is 1331211203107. The next prime is 1331211203123. The reversal of 1331211203122 is 2213021121331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 972375460281 + 358835742841 = 986091^2 + 599029^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1331211203093 and 1331211203102.
It is not an unprimeable number, because it can be changed into a prime (1331211203123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332802800779 + ... + 332802800782.
Almost surely, 21331211203122 is an apocalyptic number.
1331211203122 is a deficient number, since it is larger than the sum of its proper divisors (665605601564).
1331211203122 is an equidigital number, since it uses as much as digits as its factorization.
1331211203122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665605601563.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1331211203122 its reverse (2213021121331), we get a palindrome (3544232324453).
The spelling of 1331211203122 in words is "one trillion, three hundred thirty-one billion, two hundred eleven million, two hundred three thousand, one hundred twenty-two".
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