Base | Representation |
---|---|
bin | 11110010001001010111111… |
… | …000100111001011001001110 |
3 | 122110100021122210101112212011 |
4 | 132101022333010321121032 |
5 | 114422030133024313032 |
6 | 1151043045334331434 |
7 | 40016463636625303 |
oct | 3621127704713116 |
9 | 573307583345764 |
10 | 133121422104142 |
11 | 394645293449aa |
12 | 12b1b9a6ab9b7a |
13 | 59383b0ab9c94 |
14 | 24c317b2250aa |
15 | 105cbd8a52247 |
hex | 7912bf13964e |
133121422104142 has 8 divisors (see below), whose sum is σ = 199684307032056. Its totient is φ = 66559986426792.
The previous prime is 133121422104131. The next prime is 133121422104191. The reversal of 133121422104142 is 241401224121331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1331214221041423 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 362082973 + ... + 362450440.
It is an arithmetic number, because the mean of its divisors is an integer number (24960538379007).
Almost surely, 2133121422104142 is an apocalyptic number.
133121422104142 is a deficient number, since it is larger than the sum of its proper divisors (66562884927914).
133121422104142 is an equidigital number, since it uses as much as digits as its factorization.
133121422104142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 724625282.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 133121422104142 its reverse (241401224121331), we get a palindrome (374522646225473).
The spelling of 133121422104142 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred twenty-two million, one hundred four thousand, one hundred forty-two".
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