Base | Representation |
---|---|
bin | 11110010001001011001011… |
… | …000011101001001101101001 |
3 | 122110100022011210121022111212 |
4 | 132101023023003221031221 |
5 | 114422031041003233223 |
6 | 1151043121314402505 |
7 | 40016501630240636 |
oct | 3621131303511551 |
9 | 573308153538455 |
10 | 133121623102313 |
11 | 3946462184989a |
12 | 12b1ba42290435 |
13 | 5938413633701 |
14 | 24c3199bc718d |
15 | 105cbeb507278 |
hex | 7912cb0e9369 |
133121623102313 has 2 divisors, whose sum is σ = 133121623102314. Its totient is φ = 133121623102312.
The previous prime is 133121623102301. The next prime is 133121623102387. The reversal of 133121623102313 is 313201326121331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129553634558569 + 3567988543744 = 11382163^2 + 1888912^2 .
It is a cyclic number.
It is not a de Polignac number, because 133121623102313 - 216 = 133121623036777 is a prime.
It is a super-4 number, since 4×1331216231023134 (a number of 58 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133121623102313.
It is not a weakly prime, because it can be changed into another prime (133121623104313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560811551156 + 66560811551157.
It is an arithmetic number, because the mean of its divisors is an integer number (66560811551157).
Almost surely, 2133121623102313 is an apocalyptic number.
It is an amenable number.
133121623102313 is a deficient number, since it is larger than the sum of its proper divisors (1).
133121623102313 is an equidigital number, since it uses as much as digits as its factorization.
133121623102313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 32.
Adding to 133121623102313 its reverse (313201326121331), we get a palindrome (446322949223644).
The spelling of 133121623102313 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, six hundred twenty-three million, one hundred two thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •