13312214013431 has 4 divisors (see below), whose sum is σ = 13413833967864. Its totient is φ = 13210594059000.

The previous prime is 13312214013419. The next prime is 13312214013451. The reversal of 13312214013431 is 13431041221331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13312214013431 - 2⁴² = 8914167502327 is a prime.

It is a super-2 number, since 2×13312214013431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13312214013394 and 13312214013403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13312214013451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50809977020 + ... + 50809977281.

It is an arithmetic number, because the mean of its divisors is an integer number (3353458491966).

Almost surely, 2^{13312214013431} is an apocalyptic number.

13312214013431 is a deficient number, since it is larger than the sum of its proper divisors (101619954433).

13312214013431 is a wasteful number, since it uses less digits than its factorization.

13312214013431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101619954432.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13312214013431 its reverse (13431041221331), we get a palindrome (26743255234762).

The spelling of 13312214013431 in words is "thirteen trillion, three hundred twelve billion, two hundred fourteen million, thirteen thousand, four hundred thirty-one".