Base | Representation |
---|---|
bin | 111101111111011000… |
… | …0100101101010110111 |
3 | 110201121120201122222221 |
4 | 1323332300211222313 |
5 | 4140114012401301 |
6 | 141053403303211 |
7 | 12421626160123 |
oct | 1737660455267 |
9 | 421546648887 |
10 | 133123168951 |
11 | 515036161a3 |
12 | 2197281ab07 |
13 | c726c524b6 |
14 | 662c1b4583 |
15 | 36e2136da1 |
hex | 1efec25ab7 |
133123168951 has 2 divisors, whose sum is σ = 133123168952. Its totient is φ = 133123168950.
The previous prime is 133123168943. The next prime is 133123168967. The reversal of 133123168951 is 159861321331.
It is a weak prime.
It is an emirp because it is prime and its reverse (159861321331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133123168951 - 23 = 133123168943 is a prime.
It is a super-2 number, since 2×1331231689512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133123168898 and 133123168907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133123168921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561584475 + 66561584476.
It is an arithmetic number, because the mean of its divisors is an integer number (66561584476).
Almost surely, 2133123168951 is an apocalyptic number.
133123168951 is a deficient number, since it is larger than the sum of its proper divisors (1).
133123168951 is an equidigital number, since it uses as much as digits as its factorization.
133123168951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 116640, while the sum is 43.
The spelling of 133123168951 in words is "one hundred thirty-three billion, one hundred twenty-three million, one hundred sixty-eight thousand, nine hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •