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13312432153 is a prime number
BaseRepresentation
bin11000110010111101…
…11001100000011001
31021100202200121210201
430121132321200121
5204230440312103
610040551342201
7650615543356
oct143136714031
937322617721
1013312432153
115711580349
1226b6381961
1313420333b7
1490405762d
1552dab951d
hex3197b9819

13312432153 has 2 divisors, whose sum is σ = 13312432154. Its totient is φ = 13312432152.

The previous prime is 13312432141. The next prime is 13312432157. The reversal of 13312432153 is 35123421331.

13312432153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8796188944 + 4516243209 = 93788^2 + 67203^2 .

It is an emirp because it is prime and its reverse (35123421331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13312432153 - 29 = 13312431641 is a prime.

It is not a weakly prime, because it can be changed into another prime (13312432157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656216076 + 6656216077.

It is an arithmetic number, because the mean of its divisors is an integer number (6656216077).

Almost surely, 213312432153 is an apocalyptic number.

It is an amenable number.

13312432153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312432153 is an equidigital number, since it uses as much as digits as its factorization.

13312432153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 28.

Adding to 13312432153 its reverse (35123421331), we get a palindrome (48435853484).

The spelling of 13312432153 in words is "thirteen billion, three hundred twelve million, four hundred thirty-two thousand, one hundred fifty-three".