Search a number
-
+
13312433 is a prime number
BaseRepresentation
bin110010110010…
…000110110001
3221001100020002
4302302012301
511401444213
61153155345
7221103521
oct62620661
927040202
1013312433
117572912
12455bb55
1329b14a4
141aa7681
15127e658
hexcb21b1

13312433 has 2 divisors, whose sum is σ = 13312434. Its totient is φ = 13312432.

The previous prime is 13312399. The next prime is 13312451. The reversal of 13312433 is 33421331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9560464 + 3751969 = 3092^2 + 1937^2 .

It is an emirp because it is prime and its reverse (33421331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13312433 - 210 = 13311409 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13312463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656216 + 6656217.

It is an arithmetic number, because the mean of its divisors is an integer number (6656217).

Almost surely, 213312433 is an apocalyptic number.

It is an amenable number.

13312433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312433 is an equidigital number, since it uses as much as digits as its factorization.

13312433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 20.

The square root of 13312433 is about 3648.6206982913. The cubic root of 13312433 is about 237.0022550777.

Adding to 13312433 its reverse (33421331), we get a palindrome (46733764).

It can be divided in two parts, 1331 and 2433, that multiplied together give a palindrome (3238323).

The spelling of 13312433 in words is "thirteen million, three hundred twelve thousand, four hundred thirty-three".