Base | Representation |
---|---|
bin | 10011010111110100010… |
… | …110000010001010111111 |
3 | 11201021011201000220201102 |
4 | 103113310112002022333 |
5 | 133302342020424411 |
6 | 2455322025403315 |
7 | 165115321640642 |
oct | 23276426021277 |
9 | 4637151026642 |
10 | 1331244311231 |
11 | 47363978770a |
12 | 19600703953b |
13 | 986c71c9973 |
14 | 4860ad79a59 |
15 | 24966dddd3b |
hex | 135f45822bf |
1331244311231 has 2 divisors, whose sum is σ = 1331244311232. Its totient is φ = 1331244311230.
The previous prime is 1331244311183. The next prime is 1331244311261. The reversal of 1331244311231 is 1321134421331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331244311231 - 218 = 1331244049087 is a prime.
It is a super-2 number, since 2×13312443112312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1331244311194 and 1331244311203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331244311261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665622155615 + 665622155616.
It is an arithmetic number, because the mean of its divisors is an integer number (665622155616).
Almost surely, 21331244311231 is an apocalyptic number.
1331244311231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331244311231 is an equidigital number, since it uses as much as digits as its factorization.
1331244311231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 1331244311231 its reverse (1321134421331), we get a palindrome (2652378732562).
The spelling of 1331244311231 in words is "one trillion, three hundred thirty-one billion, two hundred forty-four million, three hundred eleven thousand, two hundred thirty-one".
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