Base | Representation |
---|---|
bin | 10011010111110100110… |
… | …111101010000101000100 |
3 | 11201021012022121201112202 |
4 | 103113310313222011010 |
5 | 133302401300003234 |
6 | 2455322542334032 |
7 | 165115456601234 |
oct | 23276467520504 |
9 | 4637168551482 |
10 | 1331253125444 |
11 | 473643757990 |
12 | 196009b8a318 |
13 | 986c8c94888 |
14 | 4860c1d1cc4 |
15 | 24967a8077e |
hex | 135f4dea144 |
1331253125444 has 24 divisors (see below), whose sum is σ = 2542373043168. Its totient is φ = 604903199040.
The previous prime is 1331253125441. The next prime is 1331253125471. The reversal of 1331253125444 is 4445213521331.
It is a junction number, because it is equal to n+sod(n) for n = 1331253125398 and 1331253125407.
It is not an unprimeable number, because it can be changed into a prime (1331253125441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5169314 + ... + 5420729.
It is an arithmetic number, because the mean of its divisors is an integer number (105932210132).
Almost surely, 21331253125444 is an apocalyptic number.
It is an amenable number.
1331253125444 is a deficient number, since it is larger than the sum of its proper divisors (1211119917724).
1331253125444 is a wasteful number, since it uses less digits than its factorization.
1331253125444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10592915 (or 10592913 counting only the distinct ones).
The product of its digits is 172800, while the sum is 38.
Adding to 1331253125444 its reverse (4445213521331), we get a palindrome (5776466646775).
The spelling of 1331253125444 in words is "one trillion, three hundred thirty-one billion, two hundred fifty-three million, one hundred twenty-five thousand, four hundred forty-four".
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