133125314441 has 4 divisors (see below), whose sum is σ = 152143216512. Its totient is φ = 114107412372.

The previous prime is 133125314417. The next prime is 133125314503. The reversal of 133125314441 is 144413521331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133125314441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133125314398 and 133125314407.

It is not an unprimeable number, because it can be changed into a prime (133125314041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9508951025 + ... + 9508951038.

It is an arithmetic number, because the mean of its divisors is an integer number (38035804128).

Almost surely, 2^133125314441 is an apocalyptic number.

It is an amenable number.

133125314441 is a deficient number, since it is larger than the sum of its proper divisors (19017902071).

133125314441 is an equidigital number, since it uses as much as digits as its factorization.

133125314441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19017902070.

The product of its digits is 17280, while the sum is 32.

Adding to 133125314441 its reverse (144413521331), we get a palindrome (277538835772).

The spelling of 133125314441 in words is "one hundred thirty-three billion, one hundred twenty-five million, three hundred fourteen thousand, four hundred forty-one".