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133130010021 = 344376670007
BaseRepresentation
bin111101111111100101…
…0101011110110100101
3110201122001121020011220
41323333022223312211
54140122240310041
6141054210050553
712422041262001
oct1737712536645
9421561536156
10133130010021
1151507468a78
1221974b79a59
13c7284a9278
14662d075701
1536e2a38d66
hex1eff2abda5

133130010021 has 4 divisors (see below), whose sum is σ = 177506680032. Its totient is φ = 88753340012.

The previous prime is 133130010017. The next prime is 133130010047. The reversal of 133130010021 is 120010031331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133130010021 - 22 = 133130010017 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133130017021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22188335001 + ... + 22188335006.

It is an arithmetic number, because the mean of its divisors is an integer number (44376670008).

Almost surely, 2133130010021 is an apocalyptic number.

It is an amenable number.

133130010021 is a deficient number, since it is larger than the sum of its proper divisors (44376670011).

133130010021 is an equidigital number, since it uses as much as digits as its factorization.

133130010021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44376670010.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 133130010021 its reverse (120010031331), we get a palindrome (253140041352).

The spelling of 133130010021 in words is "one hundred thirty-three billion, one hundred thirty million, ten thousand, twenty-one".

Divisors: 1 3 44376670007 133130010021