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13313010234103 is a prime number
BaseRepresentation
bin1100000110111010110100…
…1111101111001011110111
31202010201012120110221000221
43001232231033233023313
53221110021104442403
644151525032115211
72542555542604516
oct301565517571367
952121176427027
1013313010234103
11427301a231488
1215b0198235b07
1375754702cca8
143404d2dd867d
1518147e119dbd
hexc1bad3ef2f7

13313010234103 has 2 divisors, whose sum is σ = 13313010234104. Its totient is φ = 13313010234102.

The previous prime is 13313010234089. The next prime is 13313010234109. The reversal of 13313010234103 is 30143201031331.

It is a strong prime.

It is an emirp because it is prime and its reverse (30143201031331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13313010234103 - 225 = 13312976679671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13313010234109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656505117051 + 6656505117052.

It is an arithmetic number, because the mean of its divisors is an integer number (6656505117052).

Almost surely, 213313010234103 is an apocalyptic number.

13313010234103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13313010234103 is an equidigital number, since it uses as much as digits as its factorization.

13313010234103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13313010234103 its reverse (30143201031331), we get a palindrome (43456211265434).

The spelling of 13313010234103 in words is "thirteen trillion, three hundred thirteen billion, ten million, two hundred thirty-four thousand, one hundred three".