Base | Representation |
---|---|
bin | 10011010111111000010… |
… | …001100000010111010111 |
3 | 11201021100022002002110011 |
4 | 103113320101200113113 |
5 | 133303010404424142 |
6 | 2455332342341051 |
7 | 165120052160554 |
oct | 23277021402727 |
9 | 4637308062404 |
10 | 1331310233047 |
11 | 473672a12753 |
12 | 19602512a787 |
13 | 98707a6b162 |
14 | 48615a19a2b |
15 | 2496cab1417 |
hex | 135f84605d7 |
1331310233047 has 2 divisors, whose sum is σ = 1331310233048. Its totient is φ = 1331310233046.
The previous prime is 1331310232949. The next prime is 1331310233051. The reversal of 1331310233047 is 7403320131331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331310233047 - 215 = 1331310200279 is a prime.
It is a super-3 number, since 3×13313102330473 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331310233947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665655116523 + 665655116524.
It is an arithmetic number, because the mean of its divisors is an integer number (665655116524).
Almost surely, 21331310233047 is an apocalyptic number.
1331310233047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331310233047 is an equidigital number, since it uses as much as digits as its factorization.
1331310233047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 31.
Adding to 1331310233047 its reverse (7403320131331), we get a palindrome (8734630364378).
The spelling of 1331310233047 in words is "one trillion, three hundred thirty-one billion, three hundred ten million, two hundred thirty-three thousand, forty-seven".
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