1331320331113 has 4 divisors (see below), whose sum is σ = 1331355065488. Its totient is φ = 1331285596740.

The previous prime is 1331320331093. The next prime is 1331320331219. The reversal of 1331320331113 is 3111330231331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331320331113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1331320338113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17309631 + ... + 17386372.

It is an arithmetic number, because the mean of its divisors is an integer number (332838766372).

Almost surely, 2^{1331320331113} is an apocalyptic number.

It is an amenable number.

1331320331113 is a deficient number, since it is larger than the sum of its proper divisors (34734375).

1331320331113 is an equidigital number, since it uses as much as digits as its factorization.

1331320331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34734374.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1331320331113 its reverse (3111330231331), we get a palindrome (4442650562444).

The spelling of 1331320331113 in words is "one trillion, three hundred thirty-one billion, three hundred twenty million, three hundred thirty-one thousand, one hundred thirteen".