Base | Representation |
---|---|
bin | 101101010001101001101… |
… | …110111011010000100011 |
3 | 102000102212221202000011021 |
4 | 231101221232323100203 |
5 | 401434001014400311 |
6 | 10341154140430311 |
7 | 440533443416020 |
oct | 55215156732043 |
9 | 12012787660137 |
10 | 3111330231331 |
11 | a9a564892323 |
12 | 422bb6248397 |
13 | 1975217bb12a |
14 | aa836a2a547 |
15 | 55ded4ee171 |
hex | 2d469bbb423 |
3111330231331 has 16 divisors (see below), whose sum is σ = 3583033350400. Its totient is φ = 2646451592928.
The previous prime is 3111330231313. The next prime is 3111330231391. The reversal of 3111330231331 is 1331320331113.
It is a cyclic number.
It is not a de Polignac number, because 3111330231331 - 25 = 3111330231299 is a prime.
It is a super-2 number, since 2×31113302313312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3111330231296 and 3111330231305.
It is not an unprimeable number, because it can be changed into a prime (3111330231391) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1386421 + ... + 2853913.
It is an arithmetic number, because the mean of its divisors is an integer number (223939584400).
Almost surely, 23111330231331 is an apocalyptic number.
3111330231331 is a deficient number, since it is larger than the sum of its proper divisors (471703119069).
3111330231331 is a wasteful number, since it uses less digits than its factorization.
3111330231331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1469818.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 3111330231331 its reverse (1331320331113), we get a palindrome (4442650562444).
The spelling of 3111330231331 in words is "three trillion, one hundred eleven billion, three hundred thirty million, two hundred thirty-one thousand, three hundred thirty-one".
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