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13313213001149 is a prime number
BaseRepresentation
bin1100000110111011100101…
…0101001110110110111101
31202010201201201000120010112
43001232321111032312331
53221110430012014044
644152001114115405
72542563554235215
oct301567125166675
952121651016115
1013313213001149
114273113734356
1215b023411bb65
1375757a0458a9
14340511cdb245
15181491d1e09e
hexc1bb954edbd

13313213001149 has 2 divisors, whose sum is σ = 13313213001150. Its totient is φ = 13313213001148.

The previous prime is 13313213001139. The next prime is 13313213001157. The reversal of 13313213001149 is 94110031231331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8755385102500 + 4557827898649 = 2958950^2 + 2134907^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13313213001149 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13313213001139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656606500574 + 6656606500575.

It is an arithmetic number, because the mean of its divisors is an integer number (6656606500575).

Almost surely, 213313213001149 is an apocalyptic number.

It is an amenable number.

13313213001149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13313213001149 is an equidigital number, since it uses as much as digits as its factorization.

13313213001149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 13313213001149 in words is "thirteen trillion, three hundred thirteen billion, two hundred thirteen million, one thousand, one hundred forty-nine".