133132143354151 has 4 divisors (see below), whose sum is σ = 133163387700904. Its totient is φ = 133100899007400.

The previous prime is 133132143354113. The next prime is 133132143354179. The reversal of 133132143354151 is 151453341231331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133132143354151 - 2³¹ = 133129995870503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133132143354191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15622166985 + ... + 15622175506.

It is an arithmetic number, because the mean of its divisors is an integer number (33290846925226).

Almost surely, 2^{133132143354151} is an apocalyptic number.

133132143354151 is a deficient number, since it is larger than the sum of its proper divisors (31244346753).

133132143354151 is an equidigital number, since it uses as much as digits as its factorization.

133132143354151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31244346752.

The product of its digits is 194400, while the sum is 40.

Adding to 133132143354151 its reverse (151453341231331), we get a palindrome (284585484585482).

The spelling of 133132143354151 in words is "one hundred thirty-three trillion, one hundred thirty-two billion, one hundred forty-three million, three hundred fifty-four thousand, one hundred fifty-one".