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13313220031141 is a prime number
BaseRepresentation
bin1100000110111011100111…
…0000000011001010100101
31202010201202012020201110121
43001232321300003022211
53221110433311444031
644152001524521541
72542564001054632
oct301567160031245
952121665221417
1013313220031141
1142731176a6068
1215b02365502b1
1375757b637654
14340512c0b189
1518149275c011
hexc1bb9c032a5

13313220031141 has 2 divisors, whose sum is σ = 13313220031142. Its totient is φ = 13313220031140.

The previous prime is 13313220031123. The next prime is 13313220031151. The reversal of 13313220031141 is 14113002231331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12367811904100 + 945408127041 = 3516790^2 + 972321^2 .

It is a cyclic number.

It is not a de Polignac number, because 13313220031141 - 227 = 13313085813413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13313220031151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656610015570 + 6656610015571.

It is an arithmetic number, because the mean of its divisors is an integer number (6656610015571).

Almost surely, 213313220031141 is an apocalyptic number.

It is an amenable number.

13313220031141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13313220031141 is an equidigital number, since it uses as much as digits as its factorization.

13313220031141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13313220031141 its reverse (14113002231331), we get a palindrome (27426222262472).

The spelling of 13313220031141 in words is "thirteen trillion, three hundred thirteen billion, two hundred twenty million, thirty-one thousand, one hundred forty-one".