Base | Representation |
---|---|
bin | 11000110011000100… |
… | …01100001001100011 |
3 | 1021100211022110100001 |
4 | 30121202030021203 |
5 | 204231200414242 |
6 | 10041022040431 |
7 | 650626065661 |
oct | 143142141143 |
9 | 37324273301 |
10 | 13313294947 |
11 | 571200a5a7 |
12 | 26b6719117 |
13 | 1342276024 |
14 | 9041ddc31 |
15 | 52dbd9eb7 |
hex | 31988c263 |
13313294947 has 2 divisors, whose sum is σ = 13313294948. Its totient is φ = 13313294946.
The previous prime is 13313294941. The next prime is 13313294993. The reversal of 13313294947 is 74949231331.
It is an a-pointer prime, because the next prime (13313294993) can be obtained adding 13313294947 to its sum of digits (46).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13313294947 - 219 = 13312770659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13313294897 and 13313294906.
It is not a weakly prime, because it can be changed into another prime (13313294941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656647473 + 6656647474.
It is an arithmetic number, because the mean of its divisors is an integer number (6656647474).
Almost surely, 213313294947 is an apocalyptic number.
13313294947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13313294947 is an equidigital number, since it uses as much as digits as its factorization.
13313294947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 489888, while the sum is 46.
The spelling of 13313294947 in words is "thirteen billion, three hundred thirteen million, two hundred ninety-four thousand, nine hundred forty-seven".
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