133133000119 has 4 divisors (see below), whose sum is σ = 152152000144. Its totient is φ = 114114000096.

The previous prime is 133133000089. The next prime is 133133000131. The reversal of 133133000119 is 911000331331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133133000119 - 2¹⁵ = 133132967351 is a prime.

It is a super-2 number, since 2×133133000119² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133133000093 and 133133000102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133133060119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9509500002 + ... + 9509500015.

It is an arithmetic number, because the mean of its divisors is an integer number (38038000036).

Almost surely, 2^133133000119 is an apocalyptic number.

133133000119 is a deficient number, since it is larger than the sum of its proper divisors (19019000025).

133133000119 is an equidigital number, since it uses as much as digits as its factorization.

133133000119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19019000024.

The product of its (nonzero) digits is 729, while the sum is 25.

The spelling of 133133000119 in words is "one hundred thirty-three billion, one hundred thirty-three million, one hundred nineteen", and thus it is an aban number.