Base | Representation |
---|---|
bin | 10011010111111001100… |
… | …001011111101110111111 |
3 | 11201021101202112102102102 |
4 | 103113321201133232333 |
5 | 133303031241430413 |
6 | 2455334412015315 |
7 | 165120425333516 |
oct | 23277141375677 |
9 | 4637352472372 |
10 | 1331331201983 |
11 | 473683834a52 |
12 | 19603016153b |
13 | 9870c200603 |
14 | 4861871767d |
15 | 2496e854458 |
hex | 135f985fbbf |
1331331201983 has 2 divisors, whose sum is σ = 1331331201984. Its totient is φ = 1331331201982.
The previous prime is 1331331201947. The next prime is 1331331202031. The reversal of 1331331201983 is 3891021331331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331331201983 - 210 = 1331331200959 is a prime.
It is a super-4 number, since 4×13313312019834 (a number of 50 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331336201983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665665600991 + 665665600992.
It is an arithmetic number, because the mean of its divisors is an integer number (665665600992).
Almost surely, 21331331201983 is an apocalyptic number.
1331331201983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331331201983 is an equidigital number, since it uses as much as digits as its factorization.
1331331201983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 38.
The spelling of 1331331201983 in words is "one trillion, three hundred thirty-one billion, three hundred thirty-one million, two hundred one thousand, nine hundred eighty-three".
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