Base | Representation |
---|---|
bin | 10011010111111001100… |
… | …001100100001010110111 |
3 | 11201021101202120100100022 |
4 | 103113321201210022313 |
5 | 133303031243021101 |
6 | 2455334412235355 |
7 | 165120425440502 |
oct | 23277141441267 |
9 | 4637352510308 |
10 | 1331331220151 |
11 | 473683847669 |
12 | 19603016bb5b |
13 | 9870c20896a |
14 | 48618720139 |
15 | 2496e859a1b |
hex | 135f98642b7 |
1331331220151 has 2 divisors, whose sum is σ = 1331331220152. Its totient is φ = 1331331220150.
The previous prime is 1331331220147. The next prime is 1331331220157. The reversal of 1331331220151 is 1510221331331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331331220151 - 22 = 1331331220147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1331331220151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331331220157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665665610075 + 665665610076.
It is an arithmetic number, because the mean of its divisors is an integer number (665665610076).
Almost surely, 21331331220151 is an apocalyptic number.
1331331220151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331331220151 is an equidigital number, since it uses as much as digits as its factorization.
1331331220151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 1331331220151 its reverse (1510221331331), we get a palindrome (2841552551482).
The spelling of 1331331220151 in words is "one trillion, three hundred thirty-one billion, three hundred thirty-one million, two hundred twenty thousand, one hundred fifty-one".
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