Base | Representation |
---|---|
bin | 1100000110111100000001… |
… | …1011000011110011010001 |
3 | 1202010202000222212202122212 |
4 | 3001233000123003303101 |
5 | 3221111200441003413 |
6 | 44152021004041505 |
7 | 2542566530401022 |
oct | 301570033036321 |
9 | 52122028782585 |
10 | 13313331969233 |
11 | 427317490088a |
12 | 15b0267b33295 |
13 | 75759889abca |
14 | 340523a28c49 |
15 | 18149c4bdca8 |
hex | c1bc06c3cd1 |
13313331969233 has 2 divisors, whose sum is σ = 13313331969234. Its totient is φ = 13313331969232.
The previous prime is 13313331969227. The next prime is 13313331969239. The reversal of 13313331969233 is 33296913331331.
It is a balanced prime because it is at equal distance from previous prime (13313331969227) and next prime (13313331969239).
It can be written as a sum of positive squares in only one way, i.e., 12640748276689 + 672583692544 = 3555383^2 + 820112^2 .
It is a cyclic number.
It is not a de Polignac number, because 13313331969233 - 236 = 13244612492497 is a prime.
It is not a weakly prime, because it can be changed into another prime (13313331969239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656665984616 + 6656665984617.
It is an arithmetic number, because the mean of its divisors is an integer number (6656665984617).
Almost surely, 213313331969233 is an apocalyptic number.
It is an amenable number.
13313331969233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13313331969233 is an equidigital number, since it uses as much as digits as its factorization.
13313331969233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2125764, while the sum is 50.
The spelling of 13313331969233 in words is "thirteen trillion, three hundred thirteen billion, three hundred thirty-one million, nine hundred sixty-nine thousand, two hundred thirty-three".
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