13313441104151 has 4 divisors (see below), whose sum is σ = 13638159179904. Its totient is φ = 12988723028400.

The previous prime is 13313441104133. The next prime is 13313441104193. The reversal of 13313441104151 is 15140114431331.

13313441104151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13313441104151 - 2³⁸ = 13038563197207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13313441100151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162359037815 + ... + 162359037896.

It is an arithmetic number, because the mean of its divisors is an integer number (3409539794976).

Almost surely, 2^{13313441104151} is an apocalyptic number.

13313441104151 is a deficient number, since it is larger than the sum of its proper divisors (324718075753).

13313441104151 is an equidigital number, since it uses as much as digits as its factorization.

13313441104151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 324718075752.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 13313441104151 its reverse (15140114431331), we get a palindrome (28453555535482).

The spelling of 13313441104151 in words is "thirteen trillion, three hundred thirteen billion, four hundred forty-one million, one hundred four thousand, one hundred fifty-one".