1331388269353 has 2 divisors, whose sum is σ = 1331388269354. Its totient is φ = 1331388269352.

The previous prime is 1331388269329. The next prime is 1331388269429. The reversal of 1331388269353 is 3539628831331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1211943379689 + 119444889664 = 1100883^2 + 345608^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331388269353 - 2²¹ = 1331386172201 is a prime.

It is a super-3 number, since 3×1331388269353³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1331388269294 and 1331388269303.

It is not a weakly prime, because it can be changed into another prime (1331388269053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665694134676 + 665694134677.

It is an arithmetic number, because the mean of its divisors is an integer number (665694134677).

Almost surely, 2^{1331388269353} is an apocalyptic number.

It is an amenable number.

1331388269353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331388269353 is an equidigital number, since it uses as much as digits as its factorization.

1331388269353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8398080, while the sum is 55.

The spelling of 1331388269353 in words is "one trillion, three hundred thirty-one billion, three hundred eighty-eight million, two hundred sixty-nine thousand, three hundred fifty-three".