133140431114 has 4 divisors (see below), whose sum is σ = 199710646674. Its totient is φ = 66570215556.

The previous prime is 133140431113. The next prime is 133140431119. The reversal of 133140431114 is 411134041331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411134041331 = 13 ⋅31625695487.

It can be written as a sum of positive squares in only one way, i.e., 116770508089 + 16369923025 = 341717^2 + 127945^2 .

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133140431111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33285107777 + ... + 33285107780.

Almost surely, 2^133140431114 is an apocalyptic number.

133140431114 is a deficient number, since it is larger than the sum of its proper divisors (66570215560).

133140431114 is an equidigital number, since it uses as much as digits as its factorization.

133140431114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66570215559.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 133140431114 its reverse (411134041331), we get a palindrome (544274472445).

The spelling of 133140431114 in words is "one hundred thirty-three billion, one hundred forty million, four hundred thirty-one thousand, one hundred fourteen".