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1331404343011 is a prime number
BaseRepresentation
bin10011010111111101111…
…000100000011011100011
311201021120212011101001101
4103113331320200123203
5133303204002434021
62455345543415231
7165122304121621
oct23277570403343
94637525141041
101331404343011
11473711050986
12196050754517
13987213cba22
1448624316511
1524975ea0a91
hex135fde206e3

1331404343011 has 2 divisors, whose sum is σ = 1331404343012. Its totient is φ = 1331404343010.

The previous prime is 1331404342979. The next prime is 1331404343021. The reversal of 1331404343011 is 1103434041331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1331404343011 - 25 = 1331404342979 is a prime.

It is a super-2 number, since 2×13314043430112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1331404343021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665702171505 + 665702171506.

It is an arithmetic number, because the mean of its divisors is an integer number (665702171506).

Almost surely, 21331404343011 is an apocalyptic number.

1331404343011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331404343011 is an equidigital number, since it uses as much as digits as its factorization.

1331404343011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1331404343011 its reverse (1103434041331), we get a palindrome (2434838384342).

The spelling of 1331404343011 in words is "one trillion, three hundred thirty-one billion, four hundred four million, three hundred forty-three thousand, eleven".