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1331415256019 is a prime number
BaseRepresentation
bin10011010111111110100…
…010001000101111010011
311201021121121200210212212
4103113332202020233103
5133303214301143034
62455351013342335
7165122465643152
oct23277642105723
94637547623785
101331415256019
11473717224aa2
121960543379ab
1398723750024
1448625957599
1524976e092ce
hex135fe888bd3

1331415256019 has 2 divisors, whose sum is σ = 1331415256020. Its totient is φ = 1331415256018.

The previous prime is 1331415255917. The next prime is 1331415256049. The reversal of 1331415256019 is 9106525141331.

It is a strong prime.

It is an emirp because it is prime and its reverse (9106525141331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331415256019 - 212 = 1331415251923 is a prime.

It is a super-2 number, since 2×13314152560192 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1331415256049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665707628009 + 665707628010.

It is an arithmetic number, because the mean of its divisors is an integer number (665707628010).

Almost surely, 21331415256019 is an apocalyptic number.

1331415256019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331415256019 is an equidigital number, since it uses as much as digits as its factorization.

1331415256019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 41.

The spelling of 1331415256019 in words is "one trillion, three hundred thirty-one billion, four hundred fifteen million, two hundred fifty-six thousand, nineteen".