Base | Representation |
---|---|
bin | 11000110011001100… |
… | …00100011101101001 |
3 | 1021100220020010112012 |
4 | 30121212010131221 |
5 | 204231430441131 |
6 | 10041055525305 |
7 | 650640533162 |
oct | 143146043551 |
9 | 37326203465 |
10 | 13314312041 |
11 | 5712644778 |
12 | 26b6b29835 |
13 | 1342540c64 |
14 | 9043c6769 |
15 | 52dd3b52b |
hex | 319984769 |
13314312041 has 4 divisors (see below), whose sum is σ = 13316564352. Its totient is φ = 13312059732.
The previous prime is 13314311999. The next prime is 13314312043. The reversal of 13314312041 is 14021341331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13314312041 - 230 = 12240570217 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13314311998 and 13314312016.
It is not an unprimeable number, because it can be changed into a prime (13314312043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117265 + ... + 1129118.
It is an arithmetic number, because the mean of its divisors is an integer number (3329141088).
Almost surely, 213314312041 is an apocalyptic number.
It is an amenable number.
13314312041 is a deficient number, since it is larger than the sum of its proper divisors (2252311).
13314312041 is an equidigital number, since it uses as much as digits as its factorization.
13314312041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2252310.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13314312041 its reverse (14021341331), we get a palindrome (27335653372).
The spelling of 13314312041 in words is "thirteen billion, three hundred fourteen million, three hundred twelve thousand, forty-one".
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